(x+1)(x-5)=x^2-9

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Solution for (x+1)(x-5)=x^2-9 equation:


Simplifying
(x + 1)(x + -5) = x2 + -9

Reorder the terms:
(1 + x)(x + -5) = x2 + -9

Reorder the terms:
(1 + x)(-5 + x) = x2 + -9

Multiply (1 + x) * (-5 + x)
(1(-5 + x) + x(-5 + x)) = x2 + -9
((-5 * 1 + x * 1) + x(-5 + x)) = x2 + -9
((-5 + 1x) + x(-5 + x)) = x2 + -9
(-5 + 1x + (-5 * x + x * x)) = x2 + -9
(-5 + 1x + (-5x + x2)) = x2 + -9

Combine like terms: 1x + -5x = -4x
(-5 + -4x + x2) = x2 + -9

Reorder the terms:
-5 + -4x + x2 = -9 + x2

Add '-1x2' to each side of the equation.
-5 + -4x + x2 + -1x2 = -9 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-5 + -4x + 0 = -9 + x2 + -1x2
-5 + -4x = -9 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-5 + -4x = -9 + 0
-5 + -4x = -9

Solving
-5 + -4x = -9

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -4x = -9 + 5

Combine like terms: -5 + 5 = 0
0 + -4x = -9 + 5
-4x = -9 + 5

Combine like terms: -9 + 5 = -4
-4x = -4

Divide each side by '-4'.
x = 1

Simplifying
x = 1

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